Hi, I'm running Perl v5.8.8 compiled for linux. I was reading about the perl debugger and ran the following script with the command "perl -d": 1 #!/ usr/bin/perl 2 $_ = "foo"; 3 /foo/; 4 5 print "$&"; 6 print "\n"; As expected it prints "foo" before the newline, and if I check the value of $& in the debugger it does show "foo". However, if I omit line 5 of
