Data Conversion

hi, I am reading the perl code of Blosxom, I can not quite catch the meaning of this expressiong: %month2num = (nil=>'00', Jan=>'01', Feb=>'02', Mar=>'03', Apr=>'04', May=>'05', Jun=>'06', Jul=>'07', Aug=>'08', Sep=>'09', Oct=>'10', Nov=>'11', Dec=>'12'); @num2month = sort { $month2num{$a} <=> $month2num{$b} } keys %month2num;

Hi, I'm running Perl v5.8.8 compiled for linux. I was reading about the perl debugger and ran the following script with the command "perl -d": 1 #!/ usr/bin/perl 2 $_ = "foo"; 3 /foo/; 4 5 print "$&"; 6 print "\n"; As expected it prints "foo" before the newline, and if I check the value of $& in the debugger it does show "foo". However, if I omit line 5 of

This is an excerpt from the latest version perlfaq3.pod, which comes with the standard Perl distribution. These postings aim to reduce the number of repeated questions as well as allow the community to review and update the answers. The latest version of the complete perlfaq is at [link] .

This is an excerpt from the latest version perlfaq3.pod, which comes with the standard Perl distribution. These postings aim to reduce the number of repeated questions as well as allow the community to review and update the answers. The latest version of the complete perlfaq is at [link] .

Hi all, Assume the following REs: /(B(?:=c*))(?{'got B'})/ /(B(?:=c*)?)(?{'got B'})/ Both expressions match as expected (and set $1), BUT: the second one does n o t set $^R as it should do. However, if I say /(?>(B(?:=c+)?)(?{...})/ i.e. force Perl to eat up anything it matches, $^R is correctly set.

This is an excerpt from the latest version perlfaq3.pod, which comes with the standard Perl distribution. These postings aim to reduce the number of repeated questions as well as allow the community to review and update the answers. The latest version of the complete perlfaq is at [link] .

Hi When I create a new thread, the main thread cannot get input from <>. The code is like ------------------------------ ----------------- while ( $line = <STDIN> ) { chomp $line; execCmdLine($line); print "pp> "; ------------------------------ ------------------ In the execCmdLine function, if $line eq 'conn', a new thread is

This is an excerpt from the latest version perlfaq4.pod, which comes with the standard Perl distribution. These postings aim to reduce the number of repeated questions as well as allow the community to review and update the answers. The latest version of the complete perlfaq is at [link] .

This is an excerpt from the latest version perlfaq4.pod, which comes with the standard Perl distribution. These postings aim to reduce the number of repeated questions as well as allow the community to review and update the answers. The latest version of the complete perlfaq is at [link] .

Hi, I would like to match a pattern such as something( something_1( something_2( ... (something_n)...)something_els e_2)something_else_1) , where all the brackets pair up and there could be any number of pairs. something_1, something_2, ..., and something_n could contain '()' pair as well. I'm wondering if there is any way to do this with regex?